2.1.3 Amount of substance
Definitions
| Term | Definition |
|---|---|
| Mole | A mole is the amount of a substance that contains the Avogadro number of elementary particles. |
| Molar mass (\(M_r\)) | The mass in grams in each mole of the substance, measured in \(g \cdot mol^{-1}\). |
| Hydrated | A crystalline compound that contains water (e.g. \(CuSO_4 \cdot 5H_2O(s)\)). |
| Anhydrous | A crystalline compound containing no water (e.g. \(CuSO_4(s)\)). |
| Water of crystallisation | Water molecules that form part of the crystalline structure of a compound (e.g. \(H_2O\) in \(CuSO_4 \cdot 5H_2O(s)\)). |
| Stoichiometry | The relative quantities of substances in a reaction. |
| Standard solution | A solution of known concentration. |
| Limiting reagent | The reactant that is not in excess and will be used up in the reaction. |
Amount of substance
Amount of substance
- Symbol: \(n\)
- Measured in moles (symbol \(mol\))
- Always use decimals (not fractions) in every step of a calculation
Avogadro constant (\(N_A\))
- \(6.02 \times 10^{23} mol^{-1}\)
- The number of particles per mole
Concentration (\(c\))
- Unit = \(mol \cdot dm^{-3}\) (aka molar / M) or \(g \cdot dm^{-3}\)
- \(mol \cdot dm^{-3}\): \(c = \frac{n}{V} = \frac{\text{number of moles}}{\text{volume } (dm^3)}\)
- \(g \cdot dm^{-3}\): \(c = \frac{\text{mass } (g)}{\text{volume } (dm^3)}\)
- Conversion: \(\text{Conc } (mol \cdot dm^{-3}) = \frac{\text{Conc } (g \cdot dm^{-3})}{M_r}\)
Room temperature and pressure (RTP)
- Temp = 20°C / 293 K
- Pressure = 1 atm or \(1.01 \times 10^5\) Pa
Standard temperature and pressure (STP)
- Temp = 0°C / 273 K
- Pressure = 1 atm or \(1.01 \times 10^5\) Pa
Molar gas volume (\(V_m\))
- The volume per mole of gas at a stated temperature and pressure
- Under RTP: 1 mol = 24 \(dm^3\) = 24,000 \(cm^3\)
- Under STP: 1 mol = 22.4 \(dm^3\) = 22,400 \(cm^3\)
Experimental techniques to measure the amount of substances
| Variable measured | Method |
|---|---|
| Mass | - Use a digital mass balance - Choose a balance with a suitable resolution for the experiment |
| Volume of solution | - Use a measuring cylinder - Standard solution: use volumetric flask |
| Gas produced | - Use a gas syringe / measure mass lost on a balance and calculate the number of moles of gas produced |
Percentage yield
- \(\text{Percentage yield} = \frac{\text{actual yield}}{\text{theoretical yield}} \times 100\%\)
- Actual yield: the amount of the product obtained from a reaction
- Theoretical yield: the yield resulting from complete conversion of reactants into products
- Reasons for < 100% percentage yield
- Reaction did not go to completion (reversible reaction)
- Side reactions may have taken place along the main reaction
- Purification of the product may result in the loss of some products
Atom economy
- \(\text{Atom economy} = \frac{\text{sum of molar masses of useful products}}{\text{sum of molar masses of all products or reactants}} \times 100\%\)